2k^2+3k=5

Solution for 2k^2+3k=5 equation:

Simplifying
2k2 + 3k = 5

Reorder the terms:
3k + 2k2 = 5

Solving
3k + 2k2 = 5

Solving for variable 'k'.

Reorder the terms:
-5 + 3k + 2k2 = 5 + -5

Combine like terms: 5 + -5 = 0
-5 + 3k + 2k2 = 0

Factor a trinomial.
(-5 + -2k)(1 + -1k) = 0

Subproblem 1
Set the factor '(-5 + -2k)' equal to zero and attempt to solve:

Simplifying
-5 + -2k = 0

Solving
-5 + -2k = 0

Move all terms containing k to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + -2k = 0 + 5

Combine like terms: -5 + 5 = 0
0 + -2k = 0 + 5
-2k = 0 + 5

Combine like terms: 0 + 5 = 5
-2k = 5

Divide each side by '-2'.
k = -2.5

Simplifying
k = -2.5
Subproblem 2
Set the factor '(1 + -1k)' equal to zero and attempt to solve:

Simplifying
1 + -1k = 0

Solving
1 + -1k = 0

Move all terms containing k to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1k = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1k = 0 + -1
-1k = 0 + -1

Combine like terms: 0 + -1 = -1
-1k = -1

Divide each side by '-1'.
k = 1

Simplifying
k = 1
Solution
k = {-2.5, 1}